javasaurus: (pi r naught square)
[personal profile] javasaurus
Suppose you have a string that's about 31.4 meters long (actually 10 pi meters for those who care). Then it can be wrapped tightly around a cylinder with diameter 10 meters. If you add 6.3 meters to the string, you can form the lengthened string into a circle, with the cylinder at the center, and the space between string and cylinder is 1 meter all the way around.

The Earth is about 12,756,000 meters in diameter, or about 40,000,000 meters in circumference. Wrap a string (it'll be approximately 40Mm long) tightly around the Earth. Now make the string 6.3 meters (yes, meters!) longer, as in the previous example. If you form the string into a circle with the earth at its center (like the cylinder before), how much gap do you get between the Earth and the string?

The answer may surprise you!
You get the same gap as with the cylinder, 1 meter, all the way around!

Date: 2007-03-14 05:01 pm (UTC)
From: [identity profile] javasaurus.livejournal.com
and the surface area of a sphere (4*pi*r^2) is the derivative of the volume ((4/3)*pi*r^3)

as for "but what does it mean?" there are lots of those in my head. Probably one reason why I didn't finish my PhD.

Profile

javasaurus: (Default)
javasaurus

June 2012

S M T W T F S
     12
3456 789
101112 13141516
17181920212223
24252627282930

Most Popular Tags

Style Credit

Expand Cut Tags

No cut tags
Page generated Aug. 13th, 2025 08:32 am
Powered by Dreamwidth Studios